probability

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In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?

(A) 400
(B) 625
(C) 1,250
(D) 2,500
(E) 10,000

C

[tdadic84]

if 2 of the tagged fish in the 2nd batch were caught...the percent tagged was 4%...

2/50 = 1/25 = 4%

then to figure out how many are in the pond...simply divide 50 by 4%..

50/0.04 = 1250.

[raunekk]

1st)Fishes C,T & R = 50

2nd)Fishes C = 50

Fishes already tagged = 2/ 50 * 100 = 4%

% fishes already tagged in 2nd C= total % of tagged fishes in pond

i.e 4%

Now we know the total numbr of fishes tagged is 50

therefore 50 = 4% of X

(X= total number of fishes)

50 = 4/100 * X

X= 1250

hence C

hope this helps