Median

[vladmire]

Should I just plug in the highest and lowest values for x
highest = .99
lowest = 0.01

[weena82]

hi,

The easiest and most efficient way is to pick number x, such as 1/2. You'll get

1/x = 2

root(x) = 1/1.414

x = 1/2

x^2 = 1/4

X^3 = 1/8

Now you can see which is the medain. This approach takes about 1.5 min.