Hi Vasudha
A alone can complete the work in 5 days
B alone can complete the work in 20 days.
Is this the right answer. I can explain this if u can confirm the solution.
Work Problem
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f2001290
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(a+b)'s one day work = 1/4
Assume B can complete the work in x days.
Then B's one day work = 1/x
Since A is 4 times as fast as B,
Then A's one day work = 4(1/x)
4(1/X) + (1/X) = 1/4
Solve for x... That is the answer
Assume B can complete the work in x days.
Then B's one day work = 1/x
Since A is 4 times as fast as B,
Then A's one day work = 4(1/x)
4(1/X) + (1/X) = 1/4
Solve for x... That is the answer
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Cybermusings
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A works 4 times as fast as B. Together they can do all the work in 4 days. How many days would each require alone
If A works 4 times as fast as B--- he would take 1/4 of the time taken by B
So 1/x + 1/4x = 1/4 days
5/4x = 1/4
4x = 20
x = 20/4 = 5 days
A completes task in 5 days and B completes task in 4*5 = 20 days
If A works 4 times as fast as B--- he would take 1/4 of the time taken by B
So 1/x + 1/4x = 1/4 days
5/4x = 1/4
4x = 20
x = 20/4 = 5 days
A completes task in 5 days and B completes task in 4*5 = 20 days
