BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

greatest common divisor

Expert replies
Source: — Data Sufficiency |

by mals24 » Wed Nov 26, 2008 6:28 am
IMO C

St 1 m is prime.
m =3 n = 4 GCD = 1
m = 2 n = 4 GCD = 2
So since we don't have information about n---INSUFF

St 2 2n = 7m
m = 4, n = 14 GCD = 2
m = 2, n = 7 GCD = 1

Combining 1&2
m is prime.
The only prime number that will satisfy St 2 is 2
So m=2, n=7 GCD =1

C
Join the discussion

by rohangupta83 » Wed Nov 26, 2008 6:55 am
mals24 wrote:IMO C

St 1 m is prime.
m =3 n = 4 GCD = 1
m = 2 n = 4 GCD = 2
So since we don't have information about n---INSUFF

St 2 2n = 7m
m = 4, n = 14 GCD = 2
m = 2, n = 7 GCD = 1

Combining 1&2
m is prime.
The only prime number that will satisfy St 2 is 2
So m=2, n=7 GCD =1

C
can GCD actually be 1?
Join the discussion

by scoobydooby » Wed Nov 26, 2008 7:11 am
yes for numbers that are prime to each other
Join the discussion

by mals24 » Wed Nov 26, 2008 7:15 am
can GCD actually be 1?
Yes like scoobydooby said, GCD of all prime numbers is 1.

2 = 2*1
7 = 7*1

The highest common factor of 2 and 7 is 1.
Join the discussion

by austin » Wed Nov 26, 2008 7:17 am
GCD of 2 numbers (x,y) is the greatest/biggest number that can divide both x and y.

(x,y) GCD/HCF

2,3 1
4,5 1

RESULT: The HCF of two consectutive positive numbers is 1

2,5 1
7,23 1

RESULT: The HCF of two prime numbers is 1

IF THE HCF OF TWO NUMBERS IS 1, THEN THE TWO NUMBERS ARE CO-PRIME ie. 2 and 3 are co-prime.

Hope I have given some clarity...
Join the discussion

by rohangupta83 » Wed Nov 26, 2008 8:51 am
mals24 wrote:
can GCD actually be 1?
Yes like scoobydooby said, GCD of all prime numbers is 1.

2 = 2*1
7 = 7*1

The highest common factor of 2 and 7 is 1.
I agree with C then :)

good to have concepts refreshed
Join the discussion

by cramya » Wed Nov 26, 2008 9:01 am
One more vote for C) approach same as Mals24.


GCD : 1 (for any 2 primes this is the gcd)
Join the discussion