Divisibility

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Divisibility

by Winner2013 » Thu Oct 03, 2013 11:41 am
If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient

is there any rule for such problems? please help. thanks
Source: — Data Sufficiency |

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by Brent@GMATPrepNow » Thu Oct 03, 2013 11:54 am
Winner2013 wrote:If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.
(2) 28x is an integer.
Target question: Is it possible to write x as a terminating decimal?

This is a great candidate for rephrasing the target question. Aside: We have a free video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Given: 0 < x < 1
Let's say that x = a/b where the fraction a/b is written in simplest terms.
There's a nice rule that says something like,
If a/b results in a terminating decimal, then the denominator, b, MUST be the product of 2's and 5's only!
So, for example, if b = 20, the fraction a/b will result in a terminating decimal. The same holds true for other values of b such as 4, 5, 25, 40, 2, 8, and so on.

REPHRASED target question: Is b the product of 2's and 5's only?

Statement 1: 24x is an integer.
x = a/b. So, if 24x is an integer, b must be a divisor of 24.
So, b could equal 2, 3, 4, 6, 8, 12, or 24 [aside: I omitted 1 as a possibility, since we're told that 0 < x < 1]
So, for example, b could equal 8, in which case b IS the product of 2's and 5's only
Or b could equal 3, in which case b is NOT the product of 2's and 5's only
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT


Statement 2: 28x is an integer.
x = a/b. So, if 28x is an integer, b must be a divisor of 28.
So, b could equal 2, 4, 7, 14, or 28
So, for example, b could equal 4, in which case b IS the product of 2's and 5's only
Or b could equal 7, in which case b is NOT the product of 2's and 5's only
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 says that b could equal 2, 3, 4, 6, 8, 12, or 24
Statement 2 says that b could equal 2, 4, 7, 14, or 28
So, we can conclude that b = 2 or 4
Both of these possible b values ARE the product of 2's and 5's only.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Winner2013 » Thu Oct 03, 2013 7:26 pm
Thank you Brent. Your explanations are always very easy to understand. :-)