x^2=y+5
y= z-2
z=2x
x^2 = 2x-2+5 = 2x+3
x^2-2x-3=0
(x+1)(x-3) = 0
x= -1 or 3
Statement 1
x>0
therefore the value of x = 3
x^3+y^2+z
=>x^3+(2x-2)^2 +2x
=>x^3+4x^2-8x+4+2x
=>x^3+4x^2-6x+2x
putting value of x
=>27+36-18+6
=>51
Statement 1 alone is sufficient
Statement 2
y=4
y=z+4
z=6
z=2x=6
x=3
Even Statement 2 alone is sufficient
Both the statements alone are sufficient.
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