-
karthikpandian19
- Legendary Member
- Posts: 1665
- Joined: Thu Nov 03, 2011 7:04 pm
- Thanked: 165 times
- Followed by:70 members
Given: If an integer g have a factor f such that 1 < f < g, then g is a composite number, otherwise f is prime. Thus the question simply asks whether g is prime or composite.karthikpandian19 wrote:
Statement 1: g > 3! or g > 6
g may be prime (11, 13 etc) or may be composite (12, 15 etc.) ; NOT sufficient.
Statement 2: (11! + 11) ≥ g ≥ (11! + 2)
Each possible value of g is composite integer. Take few for example,
(1) g = (11! + 2) = (11*10*9*8*7*6*5*4*3*2*1 + 2) = 2*(11*10*9*8*7*6*5*4*3*1 + 1) => Multiple of 2
(2) g = (11! + 3) = (11*10*9*8*7*6*5*4*3*2*1 + 3) = 3*(11*10*9*8*7*6*5*4*2*1 + 1) => Multiple of 3
(3) g = (11! + 4) = (11*10*9*8*7*6*5*4*3*2*1 + 4) = 4*(11*10*9*8*7*6*5*3*2*1 + 1) => Multiple of 4
(4) Same for 5, 6, 7, 8, 9, 10, and 11; SUFFICIENT.
The correct answer is B.
