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thp510
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A rectangular box has the dimensions 12x10x8 (inches). What is the largest possible volumne of a right cylinder that is placed inside the box?
ANSWER: The radius of the cylinder must be equal to half of the smaller of the 2 dimensions that form the box's bottom. So the ANS is 200pi (V=25pi * 8).
Question: Why would I only want to use the two smallest radius for the base of the volume and not the two largest radius? For instance, if I said the bottom of the cylinder has a radius of 6 and the height was 10, then the volume would be greater (V=360pi).
ANSWER: The radius of the cylinder must be equal to half of the smaller of the 2 dimensions that form the box's bottom. So the ANS is 200pi (V=25pi * 8).
Question: Why would I only want to use the two smallest radius for the base of the volume and not the two largest radius? For instance, if I said the bottom of the cylinder has a radius of 6 and the height was 10, then the volume would be greater (V=360pi).

















