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by MBA.Aspirant » Wed Jun 29, 2011 1:30 pm
A hexagon is formed of 6 equilateral triangles, each with side = 8 (as given)

Area of equilateral triangle = s^2 √3 /4

= 8^2 √3/4 = 16 √3

Area of hexagon = 6 * 16 √3 = 96 √3


This question is from grockit right?
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by SwatiDenre » Wed Jun 29, 2011 1:56 pm
no i got it from somewhere else.
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by amit2k9 » Thu Jun 30, 2011 3:27 am
area of triangle = 3^(1/2)/4 * (side)^2 = 3^(1/2)/4 * 64

total number of equilateral triangles = 6
thus
6* 3^(1/2)* 16 = 96* 3^(1/2).
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