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colakumarfanta
- Senior | Next Rank: 100 Posts
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- Joined: Mon May 03, 2010 2:55 am
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I believe it's B.
Our restrictions are that n is prime and it's < 11.
Statement 1:
4^-n < 2^-6 --> 2^-2n < 2^-6. Same base so -2n < -6 or n > 3. That means that n could be 5 or n could be 7. NS.
Statement 2:
2^-n < 2^-6 --> Same base so -n < -6 or n > 6. That means that n could only be 7. Sufficient.
Let me know if I'm right.

















