Multiple Question

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Source: — Data Sufficiency |

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Re: Multiple Question

by bluementor » Mon Mar 02, 2009 3:51 am
oxvt wrote:Is the integer n a multiple of 15?

1) n is a multiple of 20
2) n+ 6 is a multiple of 3
1) n = 20k, where k is an integer.

n is a multiple of 15 only if 20k is divisible by 15. For this to be true, k must be a multiple of 3, but we can't establish this fact, hence insufficient.

2) n + 6 = 3m
n = 3m - 6, where m is an integer.

n is a multiple of 15 only if 3m-6 is divisible by 15. For this to be true, m must an integer value such as 7, 12, 17, etc. We cannot determine anything about the value of m, hence insufficient.

1+2)
3m - 6 = 20k
m - 2 = 20k/3

Clearly, k must be divisible by 3 because m-2 must be an integer. If k is divisible by 3, then 20k (=n) must be divisble by 15. Hence sufficient. Choose C.

-BM-

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Re: Multiple Question

by dreamzz2010 » Mon Mar 02, 2009 4:01 am
bluementor wrote:
oxvt wrote:Is the integer n a multiple of 15?

1) n is a multiple of 20
2) n+ 6 is a multiple of 3
1) n = 20k, where k is an integer.

n is a multiple of 15 only if 20k is divisible by 15. For this to be true, k must be a multiple of 3, but we can't establish this fact, hence insufficient.

2) n + 6 = 3m
n = 3m - 6, where m is an integer.

n is a multiple of 15 only if 3m-6 is divisible by 15. For this to be true, m must an integer value such as 7, 12, 17, etc. We cannot determine anything about the value of m, hence insufficient.

1+2)
3m - 6 = 20k
m - 2 = 20k/3

Clearly, k must be divisible by 3 because m-2 must be an integer. If k is divisible by 3, then 20k (=n) must be divisble by 15. Hence sufficient. Choose C.

-BM-
nice explaination bluementor