Hello,

Can you please tell me how to solve this:

The integers between 1 and 100, inclusive, are put in list A if they are divisible by 2 and in list B if they are divisible by 3. How many integers in list A are not in list B?

OA: 34

I tried to solve as follows:

A = { 2, 4, 6, 8, 10, 12, 14, 16, ... }
B = { 3, 6, 9, 12, 15, 18, 21, 24, ... }

There are ((100 - 2)/2 ) + 1 integers in A i.e. 50 integers in A

2 out of 3 are not in B.

Hence, 2/3 = ?/50

I was stuck at this point though. Can you please assist?

Thanks,
Sri