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by sana.noor » Tue Jul 30, 2013 10:47 am
Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e) 14

OA is C but my answer is d
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Source: — Data Sufficiency |

by GMATGuruNY » Tue Jul 30, 2013 11:14 am
sana.noor wrote:Two cards selected from a pair of poker. If the sum of the numbers on the card is no more than 7, how many different possible values does the product of the two numbers have?

a) 7
b) 8
c)10
d) 12
e) 14

OA is C but my answer is d
The following products are possible:
1*1 = 1.
1*2 = 2.
1*3 = 3.
1*4 = 4.
1*5 = 5.
1*6 = 6.
2*4 = 8.
2*5 = 10.
3*3 = 9.
3*4 = 12.
Total options = 10.

The correct answer is C.
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