k, k+2 , ....., k+22 be the numbersrahul.s wrote:If twelve consecutive even integers are listed in increasing order, what is the value of the largest of the twelve integers?
(1) The sum of the first six integers is 18.
(2) The sum of the first three integers is 54 less than the sum of the last three.
OA: A
Source: Knewton
1)k+ k+2 +k+4 +k+6 +k+8 +k+10 =18
6k +30 = 18
k = -12/6
k = -2
the largest k+22 = 20
2) 3k+6 +54 = 3k +22+20+18
3k +60 = 3k +60
doesn't yield an equation. Hence insufficient
[spoiler]
A[/spoiler]
