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Inequalities - Small clarification

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by ankur.agrawal » Sat Jan 15, 2011 7:08 am
2x-12 <=12 ?

I would add 12 both sides & divide by 2 which gives:

x<=12.

Is this correct to do this. We don't know the sign of x here.

Thx in advance.
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by anshumishra » Sat Jan 15, 2011 7:12 am
ankur.agrawal wrote:2x-12 <=12 ?

I would add 12 both sides & divide by 2 which gives:

x<=12.

Is this correct to do this. We don't know the sign of x here.

Thx in advance.
This is right.
We don't know the sign of "x", but we know the sign of "2" (+ve) with which we are dividing both the sides.
Thanks
Anshu

(Every mistake is a lesson learned )
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by ankur.agrawal » Sat Jan 15, 2011 7:19 am
anshumishra wrote:
ankur.agrawal wrote:2x-12 <=12 ?

I would add 12 both sides & divide by 2 which gives:

x<=12.

Is this correct to do this. We don't know the sign of x here.

Thx in advance.
This is right.
We don't know the sign of "x", but we know the sign of "2" (+ve) with which we are dividing both the sides.
Thx dude. Just had a small confusion.
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