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Wendy drove

by sanju09 » Tue Oct 18, 2011 5:07 am
Wendy drove 4 hours in a car to reach a conference she was attending. On her return trip, she followed the same route but the trip took her 1½ hours longer. If she drove 220 miles to conference, how much slower was her average speed on the return trip?
(A) 10
(B) 15
(C) 25
(D) 40
(E) 55
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by Anurag@Gurome » Tue Oct 18, 2011 5:27 am
sanju09 wrote:Wendy drove 4 hours in a car to reach a conference she was attending. On her return trip, she followed the same route but the trip took her 1½ hours longer. If she drove 220 miles to conference, how much slower was her average speed on the return trip?
Average speed in the forward trip = 220/4 = 55 miles per hour

Average speed in the return trip = 220/(4 + 1.5) = 220/5.5 = 40 miles per hour

Hence, her average speed was (55 - 40) = 15 miles per hour slower on the return trip.

The correct answer is B.
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by Abhishek009 » Tue Oct 18, 2011 6:56 am
sanju09 wrote:Wendy drove 4 hours in a car to reach a conference she was attending. On her return trip, she followed the same route but the trip took her 1½ hours longer. If she drove 220 miles to conference, how much slower was her average speed on the return trip?
(A) 10
(B) 15
(C) 25
(D) 40
(E) 55
Speed while attending the conference is (220/4) 55 miles/hr

Speed while returning from the conference is ( 220/5.5) 40 miles/hr


So on her speed was 15 miles/hr ( 55 - 40 ) slower than her speed while attending the conference...
Abhishek
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