BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

manhattan review

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Community Manager
Posts: 991
Joined: Thu Sep 23, 2010 6:19 amFollowed by: 24 members
Location: Bangalore, India
Thanked: 146 times

by shovan85 » Wed Nov 03, 2010 10:39 am
nickhar130 wrote:How many integers between 250 and 300, inclusiv, can be evenly divided by NEITHER 3 NOR 5?

a) 33
b) 28'
c) 27
d) 25
e) 24

is there a trick to this, please advise?
Yes!!! Of course there is a trick. ;)

What is the first multiple of 3 between 250 and 300? Its 252.
What is the last multiple of 3 between 250 and 300? Its 300.

How many are divisible by 3 between 252 and 300?
(300-252)/3 = 48/3 = 16 but it excludes 252. Hence 17.


What is the first multiple of 5 between 250 and 300? Its 250.
What is the last multiple of 5 between 250 and 300? Its 300.

How many are divisible by 3 between 252 and 300?
(300-250)/5 = 50/5 = 10 but it excludes 250. Hence 11.

But wait there are some integers which are multiple of 3 and 5. Thus we need to discard the integers which are multiple of LCM[3,5] = 15.

What is the first multiple of 15 between 250 and 300? Its 255.
What is the last multiple of 15 between 250 and 300? Its 300.

How many are divisible by 15 between 255 and 300?
(300-255)/15 = 45/15 = 3 but it excludes 255. Hence 4.

So, Total = 11 +17 -4 = 24

Total numbers between 250 and 300 is 300-250 + 1 = 51

Not divisible by 3 and 5 = 51 - 24 = 27
Last edited by shovan85 on Wed Nov 03, 2010 10:47 am, edited 1 time in total.
If the problem is Easy Respect it, if the problem is tough Attack it
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pmFollowed by: 88 members
Location: Milpitas, CA
Thanked: 447 times

by Rahul@gurome » Wed Nov 03, 2010 10:44 am
nickhar130 wrote:How many integers between 250 and 300, inclusiv, can be evenly divided by NEITHER 3 NOR 5?

a) 33
b) 28'
c) 27
d) 25
e) 24

is there a trick to this, please advise?
Required number of integers = Total numbers of integers - Number of integers divisible by 3 - Number of integers divisible by 5 + Number of integers divisible by 15

The term "Number of integers divisible by 15" is added because numbers like 255, 270, ... 300 are divisible by both 3 and 5. So they have been discarded twice. To incorporate them we must add the number of integers that are divisible by both 3 and 5.

Now, total number of integers between 250 and 300 inclusive = 300 - 250 + 1 = 51
Now, total number of integers between 250 and 300 inclusive that are,
  • (1) Divisible by 3 = (300 - 250)/3 + 1 = 17
    (2) Divisible 5 = (300-250)/5 + 1 = 11
    (3) Divisible by 15 = (300-250)/15 + 1 = 4
Note: The integer part of the result of the division is accounted only. This is because the number of integers itself must be an integer. 1 is added to account for the inclusion of 300.

Therefore, number of integers between 250 and 300, inclusive, that can be evenly divided by NEITHER 3 NOR 5 = 51 - 17 - 11 + 4 = 27

The correct answer is C.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pmFollowed by: 88 members
Location: Milpitas, CA
Thanked: 447 times

by Rahul@gurome » Wed Nov 03, 2010 10:50 am
shovan85 wrote:...

IMO
E
@shovan85: The question asks for How many integers between 250 and 300, inclusive, can be evenly divided by NEITHER 3 NOR 5?

Thus, the answer is not 24. It's 51 - 24 = 27.

How was your test by the way? :)
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 44
Joined: Wed Nov 03, 2010 10:07 am
Thanked: 1 times

by nickhar130 » Wed Nov 03, 2010 10:54 am
thank you all. Explanation is very clear.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1