How many randomly assembled people are needed to have a better than 50% probability that at least 1 of them was born in a leap year?
A. 1
B. 2
C. 3
D. 4
E. 5
OA soon.
A. 1
B. 2
C. 3
D. 4
E. 5
OA soon.
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Aside: I don't the GMAT would require someeone to know what a leap year is.rakeshd347 wrote:How many randomly assembled people are needed to have a better than 50% probability that at least 1 of them was born in a leap year?
A. 1
B. 2
C. 3
D. 4
E. 5
OA soon.
Hi Brent,Brent@GMATPrepNow wrote:Let's say P(born in a leap year) = 1/4 (approximately).rakeshd347 wrote:How many randomly assembled people are needed to have a better than 50% probability that at least 1 of them was born in a leap year?
A. 1
B. 2
C. 3
D. 4
E. 5
OA soon.
So, P(not born in a leap year) = 3/4
Good point, Vivek.mevicks wrote: Hi Brent,
By this logic even the answer choices D and E yield a probability of greater than 50%.
D --> 1 - 81/256 --> 175/256
E --> 1 - 243/1024 --> 781/1024
Since the question doesn't place a lower limit on the number of people (least number of people required) why should one choose option c over the other two?
Thanks & Regards,
Vivek
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