BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Set X consists of the first 100 positive even integers. Set

Expert replies
by AAPL » Thu Aug 16, 2018 5:27 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Veritas Prep

Set X consists of the first 100 positive even integers. Set Y consists of the first 100 positive multiples of 5. If the terms in both sets are combined to create a new set with no repeat elements, what is the sum of all unique terms in the new set?

A. 33250
B. 34350
C. 35750
D. 36300
E. 37500

OA A.
Join the discussion
Source: — Problem Solving |

by [email protected] » Thu Aug 16, 2018 2:25 pm
Hi All,

We're told that Set X consists of the first 100 positive EVEN integers and Set Y consists of the first 100 positive multiples of 5. If the terms in both sets are combined to create a new set with NO repeat elements, we're asked for the sum of all unique terms in the new set. This question involves 'bunching' and requires some Arithmetic.

To start, we can find the sums of Set X and Set Y without too much trouble:

Set X includes the EVEN integers from 2 to 200, inclusive (2, 4, 6, ...... 198, 200). We can 'pair' terms into pairs of 202 (re: 2 + 200, 4 + 198, etc.). This will gives us 50 pairs of 202, which totals (50)(202) = 10,100

Set Y includes the multiples of 5 from 5 to 500, inclusive (5, 10, 15, ..... 495, 500). We can 'pair' terms into pairs of 505 (re: 5 + 500, 10 + 495, etc.). This will gives us 50 pairs of 505, which totals (50)(505) = 25,250

When combining these two sets, there WILL be duplicates though - all of the multiples of 10 from 10 to 200, inclusive will be in BOTH sets. We're told NOT to count the duplicate entries though, so we would have to subtract one of each of those terms from the total. Again, we can 'bunch' the numbers into 'pairs' of 210 (10 + 200, 20 + 190, etc.). This will gives us 10 pairs of 210, which totals (10)(210) = 2100.

Total = 10,100 + 25, 250 - 2100 = 33, 250

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Jeff@TargetTestPrep » Mon Aug 20, 2018 10:51 am
AAPL wrote:Veritas Prep

Set X consists of the first 100 positive even integers. Set Y consists of the first 100 positive multiples of 5. If the terms in both sets are combined to create a new set with no repeat elements, what is the sum of all unique terms in the new set?

A. 33250
B. 34350
C. 35750
D. 36300
E. 37500

The sum of the numbers in X is (2 + 200)/2 x 100 = 202 x 50 = 10,100. Similarly, the sum of the numbers in Y is (5 + 500)/2 x 100 = 505 x 50 = 25,250. When the two sets of numbers are combined into one single set, if duplicate elements (i.e., the elements that are common in both sets) count as twice, then the sum of the new set would be 10,100 + 25,250 = 35,350. However, since the duplicate elements should only count once, not twice, we need to subtract, from 35,350, the sum of the duplicate elements. The duplicate elements are 10, 20, ..., 200, with a sum of (10 + 200)/2 x 20 = 210 x 10 = 2,100. So the sum of the new set when the duplicate elements only count once is 35,350 - 2,100 = 33,250.

Answer: A

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Join the discussion

by swerve » Mon Aug 20, 2018 1:04 pm
Sum of first 100 positive even integers: 2 + 4 + 6 + 8 + . . . + 200 = [100 (2+200)]/2 = 10100
Sum of first 100 positive multiples 5: 5 + 10 + 15 + . . . + 500 = [100 (5+500)]/2 = 25250
Sum of multiples of 10 till 200: 10 + 20 + 30 + . . . + 200 = [20 (10+200)]/2 = 2100

Therefore: Sum of all unique terms in the new set = 10100 + 25250 - 2100 = 33250. Option A. Regards!
Join the discussion