27 = 3^3
(3^3)^n = (3^2)^4
(3)^3n = 3^8
n = 8/3
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Can't seem to figure this question out
Source: Beat The GMAT — Problem Solving |
27^n=9^4
27 is 3 times bigger then 9
hence, n must be 3 bigger then 4
so
n = 12
27 is 3 times bigger then 9
hence, n must be 3 bigger then 4
so
n = 12
Think I did it the way ssmiles08 did ...
uzbek wrote:27^n=9^4
27 is 3 times bigger then 9
hence, n must be 3 bigger then 4
so
n = 12
There is no way 27^12 = 9^4....It even logically absurd. YOu need to convert them all into 3's since they are all multiples of 3 and then set them equal to each other.uzbek wrote:27^n=9^4
27 is 3 times bigger then 9
hence, n must be 3 bigger then 4
so
n = 12
Ups...
Sorry, I didn't realize that this symbol meant "^" exponent
I though it was one of those GMAT questions where they give you some weird symbols like * or @ or something
Sorry, I didn't realize that this symbol meant "^" exponent
I though it was one of those GMAT questions where they give you some weird symbols like * or @ or something
Here's how I did it.
9^4 = 9*9*9*9=3*3*3*3*3*3*3*3 aka 3^8
since 27=3*3*3, i found "n" by finding how many 27's there were in 3^8
so, (3*3*3)(3*3*3)(3*3) means there 2 and 2/3 27's in 3^8
27^2.666666666=6561=9^4
-Hope this helps
9^4 = 9*9*9*9=3*3*3*3*3*3*3*3 aka 3^8
since 27=3*3*3, i found "n" by finding how many 27's there were in 3^8
so, (3*3*3)(3*3*3)(3*3) means there 2 and 2/3 27's in 3^8
27^2.666666666=6561=9^4
-Hope this helps
Normally in such problems simplify the base to the lowest possible number, then its easier to solve.mets3145 wrote:If 27^n = 9^4
what's n?
how do i isolate n?
27^n = 9^4
3^3n = 3^8
3n=8
n=8/3
