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Modulus + Inequality

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by aditya8062 » Sat Apr 06, 2013 6:41 am
my take wud be E .plz confirm the OA
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by srcc25anu » Sat Apr 06, 2013 10:39 am
is |x-z| > |x-y|?

1. |z| > |y|
if x = 5, y = 2, z = 6 |x-z| = 1 < |x-y| = 4 (not true)
if x = 5, y = 2 and z = 12, |x-z| = 7 > |x-y| = 4 (true)
Not SUfficient

2. x < 0
No info anout y and Z
Not SUfficient

Together:
if x = -5, y = -3, z = -6 |x-z| = 1 < |x-y| = 2 (not true)
if x = -5, y = -3 and z = -10, |x-z| = 5 > |x-y| = 2 (true)
Not SUfficient

hence E
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