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by sanju09 » Mon Mar 08, 2010 1:30 am
(3 + √6)/(5 √3 - 2 √12 - √32 + √50) =
(A) -2 √3
(B) -√3
(C) √3
(D) 2 √3
(E) 2 √6
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by thephoenix » Mon Mar 08, 2010 2:44 am
sanju09 wrote:(3 + √6)/(5 √3 - 2 √12 - √32 + √50) =
(A) -2 √3
(B) -√3
(C) √3
(D) 2 √3
(E) 2 √6
(3 + √6)/(5 √3 - 2 √12 - √32 + √50)
deno=(5 √3 - 2 √12 - √32 + √50) =(5v3-4v3-4v2+5v3)=v3+v2

after rationalization: num=3v3-3v2+v18-v12 and den=1

value=3v3-3v2+3v2-2v3=v3
IMO C
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