1 alone) No - There could be 20 marbles, 6 of which are green, 12 of which are blue and 2 of which are red. P(Red) = 2/20 < 1/4

2 alone) No - P(Blue) = 2/5, so it is possible that P(Green) = 2/5 and P(Red) = 1/5 < 1/4

1 and 2) YES - P(Blue) = 1-(3/5) = 2/5, so from 1. P(Green) = 1/2*(P(Blue)) = 1/5, so P(Red) has to be 2/5 > 1/4

John must select a marble from a bag containing red,green and blue marbles.If there are 20 marbles or fewer in the bag,is the probability that he will select a red marble greater than 1/4?

why are you considering 20 marbles as total?
Please see the BOLD part.

If you consider fewer than 20, then the total, which occurs in the denominator,will decrease and hence the probability will increase. So that makes the answer E.

What is the source of this question. The word "fewer" casts doubt on the feasibility of this question

What is the answer to the question?

The probability of picking a green marble would only be half the probability of picking a blue marble if there were only blue and green marbles in a 1:2 ratio