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Source: — Data Sufficiency |
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by moneyman » Tue Nov 13, 2007 8:43 pm
Since its a DS question we dont have to solve it.We just have to find the value of n in the sequence of the eleven numbers.

(1) says that (n+(n+1)+(n+2)..(n+8))/9=7 or n+(n+1)..+(n+8)=63 . From this we can find out that 9n+36=63.Hence here the value of n or the first number can be found out.SUFFICIENT

(2) says that ((n+10)+(n+9)+..+(n+2))/9=9.Solve in the same way to get the value of n.SUFFICIENT.

So D

Is it clear??
Maxx
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by xcise_science » Wed Nov 14, 2007 6:58 am
It makes perfect sense...I didn't think to use the "(n+(n+1)+(n+2)..(n+9)" iterations.

I'll keep that in mind!

Also, when the question says ‘consecutive’, how do we know its +1 (or -1), I thought consecutive meant evenly spaced numbers?
So, you can have consecutive odd, even, tens etc….or is that not accurate?

Thanks!
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by moneyman » Thu Nov 15, 2007 6:31 am
Well unless anything is mentioned about the type of integers I assume we can take consecutive positive integers!!
Maxx
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