Coordinate Geometry

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raju232007: Master | Next Rank: 500 Posts; Posts: 133; Joined: Sat Dec 29, 2007 2:43 am; Thanked: 12 times

by raju232007 » Mon May 03, 2010 12:14 am

Is the slope of line p greater than the slope of line q?

1. The x intercept of line p is greater than that of q
2. The y intercept of line p is less than that of q

I would appreciate a detailed explanation on how to solve this one.......

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Source: Beat The GMAT — Data Sufficiency | Mon May 03, 2010 12:14 am

liferocks: Legendary Member; Posts: 576; Joined: Sat Mar 13, 2010 8:31 pmFollowed by: 1 member; Thanked: 97 times

by liferocks » Mon May 03, 2010 12:34 am

let the x and y intercept of P be x1 and y1
and q be x2 and y2
slope of p=-y1/x1 alope of q= -y2/x2

from 1 we get x1>x2..this is not sufficient to comment on the ratio y1/x1 and y2/x2
from 2 we get y1<y2..this is not sufficient to comment on the ratio y1/x1 and y2/x2

combining both y1/x1<y2/x2 or -y1/x1<-y2/x2 or slope of p>slope of q

Ans option C

"If you don't know where you are going, any road will get you there."
Lewis Carroll

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raju232007: Master | Next Rank: 500 Posts; Posts: 133; Joined: Sat Dec 29, 2007 2:43 am; Thanked: 12 times

by raju232007 » Mon May 03, 2010 3:34 am

Thank you for your prompt response...but I am still not clear with your explanation given above....It would be really helpful if you can elaborate a little more....

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liferocks: Legendary Member; Posts: 576; Joined: Sat Mar 13, 2010 8:31 pmFollowed by: 1 member; Thanked: 97 times

by liferocks » Mon May 03, 2010 4:24 am

If you point out which section you want me to explain it will be good. Else here is an alternate explanation

From 1 x intercept of line p is greater than that of q ..this is possible when slope of p is equal to q or greater or less than that of q (see pic1)

same logic for condition 2

only when we combine we can say that slope of p>slope of q (pic2)
hope this will help

[/img]

"If you don't know where you are going, any road will get you there."
Lewis Carroll

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raju232007: Master | Next Rank: 500 Posts; Posts: 133; Joined: Sat Dec 29, 2007 2:43 am; Thanked: 12 times

by raju232007 » Mon May 03, 2010 4:56 am

Gr8 explanation..Coordinate geometry becomes much easier when you solve a problem using diagrammatic approach..I used the algebraic approach, which consumed a little more time...Anyway..thanks a lot...From here on I will try to solve coordinate geometry problem using diagrams....

Btw..If anyone requires the algebraic approach, I would be glad to help

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