i think A
what is OA?
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Which is Largest?
Source: Beat The GMAT — Problem Solving |
I got B
here is what I did
first comparison
2^1/2 > 14^1/6? ---> (2^1/2)^6 > (14^1/6)^6 ---> 2^3 > 14 not true so 14^1/6 > 2^1/2
second comparison
14^1/6 < 5^1/3 ? ---> (14^1/6)^6 < (5^1/3)^6 ---> 14 < 25 true so 5^1/3 > 14^1/6
third comparison
8^1/4 > 5^1/3? ----> (8^1/4) ^12 > (5^1/3)^12 ---> 8^3 > 5 ^4 not true so 5^1/3 > 8^1/4
last comparison
11^1/5 > 5^1/3? ---> (11^1/5)^15 > (5^1/3)^15 ---> 11^3 > 5^5 not true so 5^1/3 is the largest
here is what I did
first comparison
2^1/2 > 14^1/6? ---> (2^1/2)^6 > (14^1/6)^6 ---> 2^3 > 14 not true so 14^1/6 > 2^1/2
second comparison
14^1/6 < 5^1/3 ? ---> (14^1/6)^6 < (5^1/3)^6 ---> 14 < 25 true so 5^1/3 > 14^1/6
third comparison
8^1/4 > 5^1/3? ----> (8^1/4) ^12 > (5^1/3)^12 ---> 8^3 > 5 ^4 not true so 5^1/3 > 8^1/4
last comparison
11^1/5 > 5^1/3? ---> (11^1/5)^15 > (5^1/3)^15 ---> 11^3 > 5^5 not true so 5^1/3 is the largest
Cool explanation. The way to attack it.mikeCoolBoy wrote:I got B
here is what I did
first comparison
2^1/2 > 14^1/6? ---> (2^1/2)^6 > (14^1/6)^6 ---> 2^3 > 14 not true so 14^1/6 > 2^1/2
second comparison
14^1/6 < 5^1/3 ? ---> (14^1/6)^6 < (5^1/3)^6 ---> 14 < 25 true so 5^1/3 > 14^1/6
third comparison
8^1/4 > 5^1/3? ----> (8^1/4) ^12 > (5^1/3)^12 ---> 8^3 > 5 ^4 not true so 5^1/3 > 8^1/4
last comparison
11^1/5 > 5^1/3? ---> (11^1/5)^15 > (5^1/3)^15 ---> 11^3 > 5^5 not true so 5^1/3 is the largest
