pemdas, in ur new q with 8 ppl, u have 2 sub-committies with 4 ppl, but here "M A _ one slot" u should write "M A _ two slots" ,because now u have 2 sub-c. with 4 (not 3) pplpemdas wrote:couldn't get the last one, is it something put in bold?
i'm arranging out of 8, six 6 members except for M ALalaB wrote:hey pemdas, thnx for ur help. dont u think that there is smth forgotten here. if u change the number of persons to 8, u will have 2 sub-committies with 4(!) ppl, not 3pemdas wrote: agree about this, we can do so. In new q. we have 8-2=6
we can check M A _ one slot and 6 members, 6C1=6!/5!=6 (fine)
still, I feel that I was wrong. I have read all solutions above, and I hope I understand them.
I think I misunderstood the q, and wrongly thought, that M cant be without A.
anyways, I was wrong, and my method was bad. my fault is that i didnt even get a q.stem.
I thought we need to find out M+A/all, but actually the q stem asked M+A/M+rest (rest=all-M)
