from [x]=5 we know x can be 5 and [5/3]=2 (rounded from 1.67)
c
algebra
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Anurag@Gurome
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Greatest integer less than or equal to x implies for any number x, between 0 and 1, [x] will be zero.sud21 wrote:
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For any number x between -1 and 0, [x] will be -1, since -1 is less than or equal to all the numbers between -1 ≤ x ≤ 0.
So, [x] = 5 implies x = 5
[x/3] = [5/3] = 2 approx.
The correct answer is C.
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I didn't get you last point. How could [5/3]= [1.67] should be 1 since [x]< = x.Anurag@Gurome wrote:Greatest integer less than or equal to x implies for any number x, between 0 and 1, [x] will be zero.sud21 wrote:
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For any number x between -1 and 0, [x] will be -1, since -1 is less than or equal to all the numbers between -1 ≤ x ≤ 0.
So, [x] = 5 implies x = 5
[x/3] = [5/3] = 2 approx.
The correct answer is C.
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gmatdriller
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I have the same question as the last poster.
[x] denotes the greatest integer less than or equal to x.
If x = 1.1, then [1.1] = 1, right?
similarly, [1.67] has digit "1" as the greatest integer less than 1.67.
What am i mis-interpreting here?
[x] denotes the greatest integer less than or equal to x.
If x = 1.1, then [1.1] = 1, right?
similarly, [1.67] has digit "1" as the greatest integer less than 1.67.
What am i mis-interpreting here?