BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

If xy + z = x(y+z)

Expert replies
by GMATsid2016 » Mon Nov 14, 2016 8:37 am
If xy + z = x(y+z), which of the following must be true?

A) x=0 and z=0

B) x=1 and y=1

C) y=1 and z=0

D) x=1 or y=0

E) x=1 or z=0

How come OA isE?

Please explain OR AND in choices?

I got x=1, but how come [spoiler]z=0[/spoiler]?

Thanks,

Sid
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Mon Nov 14, 2016 8:41 am
If xy + z = x(y + z), which of the following must be true:

1. x = 0 and z = 0
2. x = 1 and y = 1
3. y = 1 and z = 0
4. x = 1 or y = 0
5. x = 1 or z = 0
xy + z = x(y +z)

xy + z = xy + xz

z = xz

z - xz = 0

z(1 - x) = 0.

For the resulting equation to be valid, either z=0 or x=1.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Brent@GMATPrepNow » Mon Nov 14, 2016 8:44 am
If xy+z = x(y+z) which of the following must be true?

A. x = 0 and Z = 0
B. x = 1 and y = 1
B. y = 1 and z = 0
D. x = 1 or y = 0
E. x = 1 or Z = 0
The key word here is must.
So, for example, consider answer choice A. While it's possible that x = 0 and z = 0, it need not be the case.
For example, x=1, y=1 and z=1 is a solution to the equation. So, this eliminates A.

The solution . . .
Given: xy+z = x(y+z)
Expand: xy+z = xy + xz
Subtract xy from both sides: z = xz
Rearrange: xz - z = 0
Factor: z(x-1) = 0

This tells us that z = 0 or x = 1
Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by [email protected] » Mon Nov 14, 2016 1:23 pm
Hi GMATsid2016,

Notice how the answer choices to this question each involve two values and either an "and" or "or" qualifier. We can use those values against the prompt to determine what MUST be true.

To start, many of the answer choices include X=1, so let's see what happens when that 'condition' is met...

IF... X=1

XY + Z = X(Y+Z)
1(Y) + Z = 1(Y+Z)
Y + Z = Y + Z

X=1 certainly appears to be enough, on its own, to make the equation 'balance out' - so we wouldn't necessarily need any other restrictions on the values of Y or Z. There might be some other condition though that would also make the equation balance out, so we should take a good look at Answers D and E.

IF... Y=0

XY + Z = X(Y+Z)
X(0) + Z = X(0+Z)
X + Z = XZ

That isn't necessarily true (in fact, it's almost never true), so we can eliminate Answer D

IF... Z=0

XY + Z = X(Y+Z)
X(Y) + 0 = X(Y+0)
XY = XY

This is also balanced out, so this is another option.

Final Answer: E

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Jay@ManhattanReview » Thu Dec 15, 2016 1:36 am
GMATsid2016 wrote:If xy + z = x(y+z), which of the following must be true?

A) x=0 and z=0

B) x=1 and y=1

C) y=1 and z=0

D) x=1 or y=0

E) x=1 or z=0

How come OA isE?

Please explain OR AND in choices?

I got x=1, but how come [spoiler]z=0[/spoiler]?

Thanks,

Sid
Hi Sid,

I think you have a challenge in dealing with z = xz.

Let us pick up from here.

z = xz

You can surely cancel out z from LHS and RHS, provided that you are sure that z is not equal to 0; but you are not. So the correct approach to deal is:

z = xz => z - xz = 0 => z(1 - x) = 0 => Either z = 0 or x - 1 = 0 => z = 0 or x = 1.

Hope this helps!

-Jay

_________________
Manhattan Review GMAT Prep

Locations: New York | Tokyo | Manchester | Geneva | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion