Please explain the working of this sum.Really need the help.Thnks.The answer is in a box in the attatchment.
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A negative slope (from Statement 1) means that the line -- any line with any negative slope -- looks like this [ \ ] and there is literally no way to draw it without going into Quadrant II at some point (imagine putting an infinitely long "" anywhere on the graph pictured). Only lines with a positive slope [ / ] or a slope of 0 [ -- ] and a negative y-intercept avoid Quadrant II.rb90 wrote:Please explain the working of this sum.Really need the help.Thnks.The answer is in a box in the attatchment.
Statement 2 gives us a negative y-intercept, but a line that's [ / ] or [ -- ] could avoid quadrant II from there.
