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by aneesh.kg » Mon Jun 11, 2012 12:21 pm
Using Pythagoras' theorem,
third side: a(3)^0.5

Perimeter
= 2a + a + a(3)^0.5
= 3a + a(3)^0.5 = 60 + 20(3)^0.5
a = 20

[spoiler](B)[/spoiler] is correct.
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by aneesh.kg » Mon Jun 11, 2012 12:25 pm
Q2:
BC = [(5 + 3)^2 + (x + 3)^2]^0.5 = 17^2
[8^2 + (x + 3)^2] = 17^2
8-15-17 is a common Pythagorean triplet.
x + 3 = 15
x = 12

[spoiler](B)[/spoiler] is correct.
Aneesh Bangia
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