If -1 < x < 0, which of the following must be true?

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by GMATGuruNY » Tue Aug 06, 2013 5:49 pm
guerrero wrote:If -1 < x < 0, which of the following must be true?

I. x^3 < x^2
II. x^5 < 1 - x
III. x^4 < x^2

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II and III

OAE
Constraint: -1 < x < 0.
Thus, x is a NEGATIVE FRACTION between -1 and 0.

I: x³ < x²
Since x≠0, x²>0.
Thus, we can safely divide both sides by x²:
x³/x² < x²/x²
x < 1.
Since x is a negative fraction between -1 and 0, it must be true that x<1.
Eliminate C, which does not include statement I.

III: x� < x²
Since x≠0, x²>0.
Thus, we can safely divide both sides by x²:
x�/x² < x²/x²
x² < 1.
Since x is a negative fraction between -1 and 0, it must be true that x² < 1.
Eliminate A and B, which do not include statement III.

II: x� < 1-x
x� + x < 1.
Since x<0, x� < 0.
Thus, x� + x = negative + negative = negative.
Thus, it must be true that x� + x < 1.
Eliminate D, which does not include statement II.

The correct answer is E.
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by Matt@VeritasPrep » Tue Aug 06, 2013 5:59 pm
One approach is plugging in a value of x (say, x = -1/2) and seeing which inequalities are true.

Another is to do it algebraically.

I:

x³ < x²

Since x² must be positive (as x is not 0), dividing both sides by x² won't flip the inequality. When we divide by x², we get

x < 1

Since x is negative, this is true, and I works.

II:

x� + x < 1
x(x� + 1) < 1

Since x is negative, and (x� + 1) is positive, x(x� + 1) must be negative, and hence < 1. II is true!

III:

x� < x²

0 < x² - x�

0 < x²(1 - x²)

Since x² is positive and (1 - x²) is positive (as 0 < x² < (-1)²), this is also true. III works.

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by [email protected] » Tue Aug 06, 2013 6:05 pm
Hi guerrero,

Since the other two explanations focused on math, I'll focus on the number properties at play.

Since we're dealing with NEGATIVE FRACTIONS, we can use those number property rules against the Roman Numerals.

I. x^3 < x^2

(negative)^3 = negative
(negative)^2 = positive
Roman Numeral I is TRUE

II. x^5 < 1 - x

(negative)^5 = negative
1 - (negative) = positive
Roman Numeral II is TRUE

III. x^4 < x^2

(negative fraction)^4 vs. (negative fraction)^2
(neg frac)^4 will be a smaller, positive fraction than (neg frac)^2
Roman Numeral III is TRUE

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