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akshatgupta87
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IMO- D
|x-1|<1
x<2 and x>0
statement 1: x>2 and x<0 (sufficient)
statement 2: x <0 (sufficient)
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MAAJ
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IMO [spoiler](D)[/spoiler]
Is |x-1| < 1?
1)(x-1)² > 1
|x-1| > 1
Positive ABS: x-1 > 1 thus x > 2
Negative ABS: -x+1 > 1 thus x < 0
If you try both values, then |x-1| will always be greater than 1.
2) 0 > x
This is one of the solutions of the STMT 1 so its sufficient.
Is |x-1| < 1?
1)(x-1)² > 1
|x-1| > 1
Positive ABS: x-1 > 1 thus x > 2
Negative ABS: -x+1 > 1 thus x < 0
If you try both values, then |x-1| will always be greater than 1.
2) 0 > x
This is one of the solutions of the STMT 1 so its sufficient.
"There's a difference between interest and commitment. When you're interested in doing something, you do it only when circumstance permit. When you're committed to something, you accept no excuses, only results."
|x-1| < 1 ,can only be possible if x is a positive fraction between 0 & 1 i.e 0<x<1akshatgupta87 wrote:Q.)Is 1 > |x-1| ?
A)(x-1)^2 > 1
B) 0 > x
Someone explain..
we can verify this by testing numbers (-5,-1,-1/2,0,1/2,1,5)
Now Taking equation 1
(x-1)^2 > 1
The above equation can only be true if either, x<0 or x>2. We can verify this by testing numbers (-5,-1,-1/2,0,1/2,1,5)
So eq 1 is sufficient
Now Taking equation 2
x<0
if x<0 than |x-1| will always be greater than 1
So eq 2 is sufficient
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GMATGuruNY
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akshatgupta87 wrote:Q.)Is 1 > |x-1| ?
A)(x-1)^2 > 1
B) 0 > x
Someone explain..
Question: Is |x-1| < 1?
Case 1: x-1 < 1
x < 2
Case 2: x-1 > -1
x > 0
Question rephrased: Is 0 < x < 2?
Statement 1: (x-1)² > 1.
Case 1: x-1 > 1
x > 2.
Case 2: x-1 < -1
x < 0.
Thus, it is not possible that 0 < x < 2.
Sufficient.
Statement 2: x < 0.
Thus, it is not possible that 0 < x < 2.
Sufficient.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
