If the integers a & n are >1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a?
1) a^n=64
2) n=6
1) a^n=64
2) n=6
Answer should be C
Question states that product of first 8 positive integers i.e. 1*2*3*4*5*6*7*8 is a multiple of a^n. What is a = ?
1. a^n = 64 ==> 2^6 or 4^3 or 8^2. So, a can be equal to 2,4 or 8. So, insufficient.
2. n=6. This alone is insufficient to answer the question.
Together, the only possiblity of n=6 is when a=2. Also, 2^6 is a factor of the product of the first 8 positive integers.
Hope this helps.
