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Squash- weather inclement

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by anshumishra » Thu Dec 23, 2010 3:43 pm
[email protected] wrote:I don't agree with Manhattan's reasoning.

According to them the correct answer is 32.5%.

Please explain.
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Probability that I'll play squash if (My mother doesn't come Tomorrow) AND (Doesn't hail) AND (No Rain)
= 1/2*3/4*9/10 = 27/80 ~= 33%
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by [email protected] » Thu Dec 23, 2010 5:01 pm
Unfortunately, that's not the correct answer.
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by goyalsau » Thu Dec 23, 2010 5:48 pm
[email protected] wrote:Unfortunately, that's not the correct answer.

HI! Archit, Different kind of a question,

Its very rare that anshu got this one wrong.... after all the post that i have seen of him,

According to me, Answer should be 32.5%

There 25% of Hail & 10% chance of rain.

So 25 + 10 = 35 %

100 - 35 = 65 % chance of clear whether.

65/2 = 32.5% Mother come to bother him.

remaining 32.5% chance of play...
Saurabh Goyal
[email protected]
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EveryBody Wants to Win But Nobody wants to prepare for Win.
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by anshumishra » Thu Dec 23, 2010 5:56 pm
goyalsau wrote:
[email protected] wrote:Unfortunately, that's not the correct answer.

HI! Archit, Different kind of a question,

Its very rare that anshu got this one wrong.... after all the post that i have seen of him,

According to me, Answer should be 32.5%

There 25% of Hail & 10% chance of rain.

So 25 + 10 = 35 %

100 - 35 = 65 % chance of clear whether.

65/2 = 32.5% Mother come to bother him.

remaining 32.5% chance of play...
Thanks goyalsau for the kind words and the solution !
I guess the word "hail" didn't make sense to me and now I got it that it points to a weather condition which is not favorable.
Your solution makes perfect sense to me.

Thanks
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by captcha » Thu Dec 23, 2010 7:09 pm
mother come = 50% chance

Hail = 25% chance

Rain = 10% chance

You can play if mom doesn't come & no hail & no rail

Probability of playing = P(no mom)*P(no hail)*P(no rain)

P(play) = .5*.75*.9

P(play)=33.75%

if hail & rain cannot come together;

P(play) = .5*(1-.25-.1)

P(play) = 32.5%
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