Inequality Problem

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Inequality Problem

by Strongt » Fri Dec 16, 2011 7:56 am
If 4/x<1/3 what is the possible range of values for x?

in case 1:

x > 0

4/x < 1/3
12>x

It says on the MGMAT Guide: If x and y are positive then flip the inequality if 1/3 > 1/5 then 3 < 5

and assumming both sides are positive in case 1, i flipped the inequality


What am I missing here?
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by GMATGuruNY » Fri Dec 16, 2011 8:13 am
Strongt wrote:If 4/x<1/3 what is the possible range of values for x?

in case 1:

x > 0

4/x < 1/3
12>x

It says on the MGMAT Guide: If x and y are positive then flip the inequality if 1/3 > 1/5 then 3 < 5

and assumming both sides are positive in case 1, i flipped the inequality


What am I missing here?
To apply the reasoning suggested by the guide, we need to flip not only the direction of the inequality but also EACH FRACTION:

4/x < 1/3 ---> x/4 > 3/1.
Thus:
x/4 > 3
x > 12.

Another approach: When the inequality is restricted to positive numbers, we can simply cross-multiply :
4/x < 1/3
3*4 < x*1
12 < x.
I favor this approach because it does not require that we flip the direction of the inequality.
Last edited by GMATGuruNY on Fri Dec 16, 2011 8:14 am, edited 1 time in total.
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by CappyAA » Fri Dec 16, 2011 8:14 am
You only flip the inequality if one side is positive and the other is negative. If both sides are positive, you do not flip the inequality.

So in Case 1 where x > 0

4/x < 1/3
12 < x

This makes sense because 4/12 can be simplified to 1/3. A larger value of x would give a smaller number and satisfy the inequality.

For Case 2 where x < 0

Any negative number will be less than 1/3. So all negative values of x will satisfy the equation.

So the possible range of values for x are:

[spoiler]x < 0 OR x > 12[/spoiler]
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by Strongt » Fri Dec 16, 2011 8:41 am
GMATGuruNY wrote:
Strongt wrote:If 4/x<1/3 what is the possible range of values for x?

in case 1:

x > 0

4/x < 1/3
12>x

It says on the MGMAT Guide: If x and y are positive then flip the inequality if 1/3 > 1/5 then 3 < 5

and assumming both sides are positive in case 1, i flipped the inequality


What am I missing here?
To apply the reasoning suggested by the guide, we need to flip not only the direction of the inequality but also EACH FRACTION:

4/x < 1/3 ---> x/4 > 3/1.
Thus:
x/4 > 3
x > 12.

Another approach: When the inequality is restricted to positive numbers, we can simply cross-multiply :
4/x < 1/3
3*4 < x*1
12 < x.
I favor this approach because it does not require that we flip the direction of the inequality.
That's awesome
Great explaination

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