Chloe gets: 2/3 remaining = 32
==> Bob gets: $4 + $16 = $20
I expected a trap in your question.
Tough word problem - dividing $
Got stuck in calculation and spent around 4 mins to solve. This is the simplest one I found here. Thanks for solution kamu. Good one.kamu wrote:Bob took $4 + 1/3 of leftover..
that implies 2/3rds is left for Chloe..
if 2/3 of leftover = $32
1/3 of leftover = $16
$16+$4 = $20.
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susahntgupta402
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Looks like I am the only lateral thinker in the group
Bob + Chloe = X
Bob = 4 + x/3
Chloe = (2X/3) - 4 = 32 ; X= 54
Bob = 4+ 54/3 = 22
Bob + Chloe = X
Bob = 4 + x/3
Chloe = (2X/3) - 4 = 32 ; X= 54
Bob = 4+ 54/3 = 22
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Brent@GMATPrepNow
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Sorry, but Bob receives $20susahntgupta402 wrote:Looks like I am the only lateral thinker in the group
Bob + Chloe = X
Bob = 4 + x/3
Chloe = (2X/3) - 4 = 32 ; X= 54
Bob = 4+ 54/3 = 22
Cheers,
Brent
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Tricky problem Brent!
Brent@GMATPrepNow wrote:Nice work, Logitech
My solution is below. Note that we don�t need to consider Ann�s portion in the solution. We can just let K be the money remaining after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob�s portion, we have $32 for Chloe.
So, we get K � Bob�s $ = 32
The equation is K-4 � (K-4)/3 = 32
Solve for K (K=52) and then determine Bob�s portion ($20).
The answer is, indeed, A
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akash singhal
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answer is A 20
since we know last remaining part is 32
we can say that
Let the remaining money after first Ann took her share be x
So bob will have x/3 part
and we know
x-x/3=32
Solving we get x = 48
So, bob gets (x/3)+4 = 20$
I guess i understood the question correct
Thanks...
since we know last remaining part is 32
we can say that
Let the remaining money after first Ann took her share be x
So bob will have x/3 part
and we know
x-x/3=32
Solving we get x = 48
So, bob gets (x/3)+4 = 20$
I guess i understood the question correct
Thanks...
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nikhilgmat31
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What about doing the solution in following way
lets total amount be x
1. A = 4 + (x-4)/2 = (x + 4)/2
2. B = 4 + 1/3 of remaining = 4 + (x - (x+4)/2)/3 = (x+20)/6
3. C = 32
C = x-A-B
32 = x- (x+4)/2 - (x+20)/6
x= 112
A = (x+4)/2 = (112+4)/2 = 58
B = (x+20)/6 = (112+20)/6 = 22
C = 32
To confirm 58+22+32 = 112
So Answer is 22
Please review & confirm.
lets total amount be x
1. A = 4 + (x-4)/2 = (x + 4)/2
2. B = 4 + 1/3 of remaining = 4 + (x - (x+4)/2)/3 = (x+20)/6
3. C = 32
C = x-A-B
32 = x- (x+4)/2 - (x+20)/6
x= 112
A = (x+4)/2 = (112+4)/2 = 58
B = (x+20)/6 = (112+20)/6 = 22
C = 32
To confirm 58+22+32 = 112
So Answer is 22
Please review & confirm.
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nikhilgmat31
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You calculated Bob's value wrongly.
Bob receives $4 plus one third of what remains -> 4 + 44/3 = 56/3
It should be 4+ 48/3 = 20
Bob receives $4 plus one third of what remains -> 4 + 44/3 = 56/3
It should be 4+ 48/3 = 20
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deepak4mba
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