Administrators and teachers

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by anuprajan5 » Sat Oct 27, 2012 12:56 am
George,

Here's my solution

The question basically gives us the split which then translates to

Female: Male = 360:180
Teachers: Administrators = 405:135

Since 1/3 of the admin were male, that makes it 45, thereby making 90 of the admin female.

Since we know the total females were 360, then 270 females were teachers.
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Anup

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by GMATGuruNY » Sat Oct 27, 2012 6:35 am
There were twice as many females as males.
Thus, F:M = 2:1.
Since 2+1 = 3, and the total number of people = 540, the multiplier for the ratio = 540/3 = 180:
F:M = 180(2:1) = 360:180.

There were 3 times as many administrators as teachers.
Thus, T:A = 3:1.
Since 3+1 = 4, and the total number of people = 540, the multiplier for the ratio = 540/4 = 135:
T:A = 135(3:1) = 405:135.

Since 1/3 of the administrators are male, the number of male administrators = (1/3)(135) = 45.

Plug all of these known values into a GROUP GRID and complete the grid so that each row/column adds up to the TOTAL for that row/column:
__________________F______M________Total

A:_______________90______45_________135

T:______________270______135________405

total:___________360______180_________540
Female teachers = 270.

The correct answer is D.
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