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society

by shashank.ism » Tue Feb 09, 2010 12:59 pm
On January 1, 2004 two new societies, SI and S2, are formed, each with n members. On the first day of each subsequent month, S1 adds b members while S2 multiplies its current number of members by a constant factor r. Both the societies have the same number of members on July 2, 2004. If b =10.5n, what is the value of r?

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by sanjayviti » Tue Feb 16, 2010 3:27 am
shashank.ism wrote:On January 1, 2004 two new societies, SI and S2, are formed, each with n members. On the first day of each subsequent month, S1 adds b members while S2 multiplies its current number of members by a constant factor r. Both the societies have the same number of members on July 2, 2004. If b =10.5n, what is the value of r?

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Solve nr^6=n+6b where b=10.5n
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by harsh.champ » Thu Feb 18, 2010 4:37 am
shashank.ism wrote:On January 1, 2004 two new societies, SI and S2, are formed, each with n members. On the first day of each subsequent month, S1 adds b members while S2 multiplies its current number of members by a constant factor r. Both the societies have the same number of members on July 2, 2004. If b =10.5n, what is the value of r?

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We get that on July 2, 2004,
For S1:-No. of members = n+6b
For S2:-No. of members = nr^6
Now,S1 = S2
Hence, n+6b = nr^6
Also,b=10.5n
So,n + 63n = nr^6
[spoiler]so, r^6 = 64
So, r=2 Hence A.[/spoiler]
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