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by srisl11 » Sun Dec 07, 2008 10:50 am
2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)

So x must be an integer for 2x to be even

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by Zipper » Sun Dec 07, 2008 10:50 am
An interesting problem indeed. Thanks Stuart.

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by tritrantran » Tue Dec 09, 2008 2:32 pm
srisl11 wrote:2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)

So x must be an integer for 2x to be even
Can X be even and not be an integer?

2(1.6) = 3.2 (even)

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by cramya » Tue Dec 09, 2008 2:42 pm
According to Stuart when we say even it implies even integer. Even and odd only applies to integers.


Refer to his post here(it may be helpful):

https://www.beatthegmat.com/divisibility ... 24929.html

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by Stuart@KaplanGMAT » Tue Dec 09, 2008 2:47 pm
tritrantran wrote:
srisl11 wrote:2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)

So x must be an integer for 2x to be even
Can X be even and not be an integer?

2(1.6) = 3.2 (even)
3.2 is NOT even. By definition, only integers are even or odd. For any number x to be an even integer, it must be true that:

x/2 = integer.
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by anayeri » Tue Dec 09, 2008 6:52 pm
What's the general rule of thumb on assumptions Stuart?

I feel like on most cases - there's some degree of assuming. Are there certain things that we should be looking out for? (ie integers would be a good example: "never assume an integer unless otherwise stated")?

Any other ones that are common assumption errors?

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by Stuart@KaplanGMAT » Tue Dec 09, 2008 7:08 pm
anayeri wrote:What's the general rule of thumb on assumptions Stuart?

I feel like on most cases - there's some degree of assuming. Are there certain things that we should be looking out for? (ie integers would be a good example: "never assume an integer unless otherwise stated")?

Any other ones that are common assumption errors?
The general rule of thumb is: never assume anything.

Unless you're given explicit info in data sufficiency questions, you don't know anything except:

1) all numbers used are 'real' numbers; and
2) the two statements will never contradict one another.
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by anayeri » Tue Dec 09, 2008 9:07 pm
got it, thanks as always Stuart!

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by vishubn » Wed Dec 10, 2008 9:46 am
Thanksa lot stuart :) !! indeed it was a very interesting problem

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by earth@work » Wed Dec 10, 2008 7:07 pm
hope i m able to get out of my habit of assuming x - integer before my GMAT test.. :-(

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by pbanavara » Sun Dec 14, 2008 3:48 pm
Oh man - This one stung me bad. Thanks for posting the question and for the explanation too

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The whole truth

by naveedakhan » Tue Dec 16, 2008 3:34 pm
2x can either be even or odd, doesn't matter, according the statement 1, we only take the values of x for which the compete statement (2x-1) is odd.
The only reason of ruling out A would be if x=0 because 2(0)-1=-1 which is odd but that x=0 is even, otherwise for any other values, either fractions or negatives, as long as 2x-1 churns out an odd number, the value for x can be taken as such.

Stuart...please comment

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Re: The whole truth

by Stuart@KaplanGMAT » Wed Dec 17, 2008 12:18 am
naveedakhan wrote:2x can either be even or odd, doesn't matter, according the statement 1, we only take the values of x for which the compete statement (2x-1) is odd.
The only reason of ruling out A would be if x=0 because 2(0)-1=-1 which is odd but that x=0 is even, otherwise for any other values, either fractions or negatives, as long as 2x-1 churns out an odd number, the value for x can be taken as such.

Stuart...please comment
2x MUST be even according to statement (1).

If 2x - 1 = odd, then we can say that:

2x = odd + 1

and any odd number + 1 will give you an even number.

However, just knowing that 2x is even doesn't help us decide if x is odd or even, it only tells us that x is an integer.

2x = even
x = even/2

and every even number is divisible by 2, so we know that x must be an integer.
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by sdilmanian » Tue Jun 07, 2011 6:29 am
Stuart Kovinsky wrote:
srisl11 wrote:Is x odd?

1) 2x-1 is odd
2) x^3 is odd


OA after some discussions please ...
Source :Kaplan
Never make assumptions!

To get (B), one has to assume that x is an integer. However, we're never told that's the case.

Is x odd?

(1) 2x - 1 = odd
2x = even

For 2x to be even, x could be an even or odd integer: insufficient.

(2) x^3 = odd

For x^3 to be odd, x could be an odd integer or the cube root of an odd integer: insufficient.

Together: from (1), we know that x is an integer; from (2), we know that if x is an integer, it must be odd. Therefore, we now know that x must be an odd integer: sufficient.

Together sufficient, apart insufficient: choose (C).

Stuart, I understand your response until the last part of your response: "Together:...". If, from (2), x could potentially be a non-integer such as the cube root of 7, how can we conclude that x is an odd integer? Integer (odd or even) + non-integer is not equal to an odd integer, right??

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by sdilmanian » Tue Jun 07, 2011 6:32 am
Oh man, nevermind!! For some reason I was trying to add the outcomes of clause 1 and 2 instead of seeing them separately.
Got it now, thanks.