2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)
So x must be an integer for 2x to be even
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tritrantran
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Can X be even and not be an integer?srisl11 wrote:2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)
So x must be an integer for 2x to be even
2(1.6) = 3.2 (even)
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cramya
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According to Stuart when we say even it implies even integer. Even and odd only applies to integers.
Refer to his post here(it may be helpful):
https://www.beatthegmat.com/divisibility ... 24929.html
Refer to his post here(it may be helpful):
https://www.beatthegmat.com/divisibility ... 24929.html
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3.2 is NOT even. By definition, only integers are even or odd. For any number x to be an even integer, it must be true that:tritrantran wrote:Can X be even and not be an integer?srisl11 wrote:2x-1 is odd => 2x is even
2x will be even only if x is an integer
2(1.5) = 3 (odd)
2(4.5) = 9 (odd)
So x must be an integer for 2x to be even
2(1.6) = 3.2 (even)
x/2 = integer.

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anayeri
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What's the general rule of thumb on assumptions Stuart?
I feel like on most cases - there's some degree of assuming. Are there certain things that we should be looking out for? (ie integers would be a good example: "never assume an integer unless otherwise stated")?
Any other ones that are common assumption errors?
I feel like on most cases - there's some degree of assuming. Are there certain things that we should be looking out for? (ie integers would be a good example: "never assume an integer unless otherwise stated")?
Any other ones that are common assumption errors?
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The general rule of thumb is: never assume anything.anayeri wrote:What's the general rule of thumb on assumptions Stuart?
I feel like on most cases - there's some degree of assuming. Are there certain things that we should be looking out for? (ie integers would be a good example: "never assume an integer unless otherwise stated")?
Any other ones that are common assumption errors?
Unless you're given explicit info in data sufficiency questions, you don't know anything except:
1) all numbers used are 'real' numbers; and
2) the two statements will never contradict one another.

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Oh man - This one stung me bad. Thanks for posting the question and for the explanation too
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naveedakhan
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2x can either be even or odd, doesn't matter, according the statement 1, we only take the values of x for which the compete statement (2x-1) is odd.
The only reason of ruling out A would be if x=0 because 2(0)-1=-1 which is odd but that x=0 is even, otherwise for any other values, either fractions or negatives, as long as 2x-1 churns out an odd number, the value for x can be taken as such.
Stuart...please comment
The only reason of ruling out A would be if x=0 because 2(0)-1=-1 which is odd but that x=0 is even, otherwise for any other values, either fractions or negatives, as long as 2x-1 churns out an odd number, the value for x can be taken as such.
Stuart...please comment
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2x MUST be even according to statement (1).naveedakhan wrote:2x can either be even or odd, doesn't matter, according the statement 1, we only take the values of x for which the compete statement (2x-1) is odd.
The only reason of ruling out A would be if x=0 because 2(0)-1=-1 which is odd but that x=0 is even, otherwise for any other values, either fractions or negatives, as long as 2x-1 churns out an odd number, the value for x can be taken as such.
Stuart...please comment
If 2x - 1 = odd, then we can say that:
2x = odd + 1
and any odd number + 1 will give you an even number.
However, just knowing that 2x is even doesn't help us decide if x is odd or even, it only tells us that x is an integer.
2x = even
x = even/2
and every even number is divisible by 2, so we know that x must be an integer.

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sdilmanian
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Stuart Kovinsky wrote:Never make assumptions!srisl11 wrote:Is x odd?
1) 2x-1 is odd
2) x^3 is odd
OA after some discussions please ...
Source :Kaplan
To get (B), one has to assume that x is an integer. However, we're never told that's the case.
Is x odd?
(1) 2x - 1 = odd
2x = even
For 2x to be even, x could be an even or odd integer: insufficient.
(2) x^3 = odd
For x^3 to be odd, x could be an odd integer or the cube root of an odd integer: insufficient.
Together: from (1), we know that x is an integer; from (2), we know that if x is an integer, it must be odd. Therefore, we now know that x must be an odd integer: sufficient.
Together sufficient, apart insufficient: choose (C).
Stuart, I understand your response until the last part of your response: "Together:...". If, from (2), x could potentially be a non-integer such as the cube root of 7, how can we conclude that x is an odd integer? Integer (odd or even) + non-integer is not equal to an odd integer, right??
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sdilmanian
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Oh man, nevermind!! For some reason I was trying to add the outcomes of clause 1 and 2 instead of seeing them separately.
Got it now, thanks.
Got it now, thanks.