Given the constraints, here is how I tackled the problem.
24 Children – since we are dealing with people, all numbers should be integers.
We want to maximize the number while ensuring a few things…
The total # of men is an even number AND the total number of women is a factor of 3. Given the # men has to be even, we know the number of women also need to be even.
So, the first number we can find for women is 6 (a factor of 3 and even), which leaves 18 men. The answer is calculated by taking ½ of the men = 9 and 1/3 of the women = 2 equaling 11 (Answer B)
I would love to see this solved algebraically by one of our quantitative wizards!
Thanks - T
students
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Travis_1234567890
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jawanindia2007
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my ans - 11
the number of boys and girls has to be multiple of 6.so the combinations possible are (12,12) ; (6,18) ; (18,6) and the last combination gives maximum number ie 9 and 2.
the number of boys and girls has to be multiple of 6.so the combinations possible are (12,12) ; (6,18) ; (18,6) and the last combination gives maximum number ie 9 and 2.
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gmattakers
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