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probability!

Expert replies
by Ozlemg » Thu Aug 04, 2011 8:36 am
In a group of 8 semifinalists, all but 2 will advance to the final round. If in the final round only the top 3 will be awarded medals, then how many groups of medal winners are possible?
(A) 20
(B) 56
(C) 120
(D) 560
(E) 720
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Source: — Data Sufficiency |

by Frankenstein » Thu Aug 04, 2011 8:40 am
Hi,
Of the 8 people, we need to pick a group of 3.
It will be done in 8C3 = 56 ways

Hence, B

Btw, this is not probability :)
Cheers!

Things are not what they appear to be... nor are they otherwise
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by HSPA » Thu Aug 04, 2011 9:08 am
Why havent you chose 3 out of 6.. and make it 20
Frankenstein wrote:Hi,
Of the 8 people, we need to pick a group of 3.
It will be done in 8C3 = 56 ways

Hence, B

Btw, this is not probability :)
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
Regards,
HSPA.
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by Frankenstein » Thu Aug 04, 2011 9:16 am
HSPA wrote:Why havent you chose 3 out of 6.. and make it 20
Frankenstein wrote:Hi,
Of the 8 people, we need to pick a group of 3.
It will be done in 8C3 = 56 ways

Hence, B

Btw, this is not probability :)
Hi,
Each of the 8 semifinalists is equally likely to win a medal. So, we have to consider all 8.
Cheers!

Things are not what they appear to be... nor are they otherwise
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by Deepthi Subbu » Fri Aug 05, 2011 4:02 am
Please help me understand this

1. Only 6 will be entering the final round so I am still confused the reason behind considering all 8.
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by Frankenstein » Fri Aug 05, 2011 5:31 am
Deepthi Subbu wrote:Please help me understand this

1. Only 6 will be entering the final round so I am still confused the reason behind considering all 8.
Hi,
We do not know which two specific persons will get knocked out. If we know the two persons who are definitely knocked out, then we need to pick 3 from the remaining 6.
Lets say : Semi Finalists are: 1,2,3,4,5,6,7,8 and we know that 7,8 are knocked out. We are sure that 1,2,3,4,5,6 are the only ones making final. So, we can use 6C3.

But, in the given question everyone is equally likely to get knocked out. So, we have to select 3 from the given 8. Please, think about the difference between the two questions.
Cheers!

Things are not what they appear to be... nor are they otherwise
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by wellsronald18 » Tue Aug 16, 2011 1:13 am
It's got to be D. the equation would be 8C6 * 6C3= (8! /6! 2!)*(6! /3! 3!) = 28*20 = 560
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