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prashanthichennupati
- Junior | Next Rank: 30 Posts
- Posts: 14
- Joined: Tue Nov 23, 2010 7:21 am
If x and y are nonzero integers, is (x-1 + y-1)-1 > [(x-1)(y-1)]-1 ?
(1) x = 2y
(2) x + y > 0
Please see my analysis below.Rephrased the question as
Is xy/x+y > xy??
(1) INSUFFICIENT.
Substituted x=2y in the equation which leads to the equation ((2y^2)/(3y))>(2y^2) which means 1/3y >1
When y=-2 and 2 the value is always less than 1
when y=1/3 or 1/6 then value is greater than 1
Hence Insufficient
(2) INSUFFICIENT.
X+Y can take values 1/2, 1, 2 . In first case 1/(X+Y)>1. In second Case 1/(X+Y)=1. In third Case 1/(X+Y)<1. Hence Insufficient.
(3) TOGETHER ALSO INSUFFICIENT
Hence my pick was E. But OA for this problem is Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Please Explain.
Thanks in Advance.
(1) x = 2y
(2) x + y > 0
Please see my analysis below.Rephrased the question as
Is xy/x+y > xy??
(1) INSUFFICIENT.
Substituted x=2y in the equation which leads to the equation ((2y^2)/(3y))>(2y^2) which means 1/3y >1
When y=-2 and 2 the value is always less than 1
when y=1/3 or 1/6 then value is greater than 1
Hence Insufficient
(2) INSUFFICIENT.
X+Y can take values 1/2, 1, 2 . In first case 1/(X+Y)>1. In second Case 1/(X+Y)=1. In third Case 1/(X+Y)<1. Hence Insufficient.
(3) TOGETHER ALSO INSUFFICIENT
Hence my pick was E. But OA for this problem is Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Please Explain.
Thanks in Advance.
