Singh,
I am sure that this has been explained before on this forum atleast a few times but here it goes. Please use the search option if possible. This way u dont have to wait on a response since they have been answered already(saves u time).
sqrt( -x |x|)
Definition of modulus
|x| = x if x>=0
|x| = -x if x<0
In the given problem x is negative
Applying the defnition here |x| = -x
sqrt(-x * -x) = sqrt(x^2) = +ve x
So this +ve x is - (original x which is negative)
So -x is the answer.
Regards,
CR
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
GMAT-Prep Q
Source: Beat The GMAT — Problem Solving |
Thanks Cramya !!! Looking at the question, it never occurred to me that GMAT can trick you on such so called obvious questions 
cramya
could you please explain definition of modulus and generally the whole process
could you please explain definition of modulus and generally the whole process
sqrt( -x |x|)
Definition of modulus
|x| = x if x>=0
|x| = -x if x<0
In the given problem x is negative
Applying the defnition here |x| = -x
sqrt(-x * -x) = sqrt(x^2) = +ve x
So this +ve x is - (original x which is negative)
















