each quarter

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each quarter

by shahdevine » Sat Aug 29, 2009 8:22 pm
At the end of each quarter-year the value of the stock of a certain company is x times more expensive. If at the start of first quarter of 1980 the price of the stock was $3 and at the end of the last quarter of 1985 the price of the stock was $9, what is x?

will post oa after some discussion.
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by bharathh » Sat Aug 29, 2009 8:52 pm
1980 Q1 3+x
1985 Q4 3+24x

24x = 9-3 =6

x = 1/4

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by heshamelaziry » Sat Aug 29, 2009 9:02 pm
Between January 1 1980 to December 31 1985 there are 24 quarters ( 4*6).

Profit is 9-3=6

6/24=.25 or quarter of a dollar profit every quarter.

IMO 1/4

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by fruti_yum » Tue Sep 01, 2009 7:32 am
bharathh wrote:1980 Q1 3+x
1985 Q4 3+24x

24x = 9-3 =6

x = 1/4
Bharathh... The question says x times more expensive. It does not say increases by x..

You should be multiplying by x not adding..

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by Matmasi » Tue Sep 01, 2009 8:43 am
Hi,
i thought that the problem should be started in this way:
3*(1+x)^20=9
Since 3, increase of a percent constantly every month:
3(1+x)*(1+x)*(1+x)*(1+x)= 3(1+x)^4 should be the value of the dollars at the end of the first year.

Unfortunately, then I don't see how to calculate in a easy way the value of x...
Any help?

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by life is a test » Tue Sep 01, 2009 9:02 am
Matmasi wrote:Hi,
i thought that the problem should be started in this way:
3*(1+x)^20=9
Since 3, increase of a percent constantly every month:
3(1+x)*(1+x)*(1+x)*(1+x)= 3(1+x)^4 should be the value of the dollars at the end of the first year.

Unfortunately, then I don't see how to calculate in a easy way the value of x...
Any help?
shouldn't it be 3(1+x)^24=9?
I cant seem to figure out how to progress from there either. If you simplify it you get (1+x)^24 = 3 --> x = 3^(1/24) - 1 --> what now??

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Re: each quarter

by Stuart@KaplanGMAT » Tue Sep 01, 2009 9:43 am
shahdevine wrote:At the end of each quarter-year the value of the stock of a certain company is x times more expensive. If at the start of first quarter of 1980 the price of the stock was $3 and at the end of the last quarter of 1985 the price of the stock was $9, what is x?

will post oa after some discussion.
We can solve this problem using the compound interest formula.

Total of Principle + Interest = P(1 + r)^t

P = starting principle
r = interest rate per compound period
t = # of compound periods

In this question:

Total of Principle + Interest = 9
P = 3
r = x/100 (we use x/100 to convert from a percent to a fraction)
t = 24 (6 years, compounded quarterly)

So, we get the equation:

9 = 3(1 + x/100)^24

Now, as you may note, there is no way to actually solve this equation in under 2 minutes (unless you can take the 24th root of 3 in your head, which seems unlikely).

So, I come to 1 of 2 conclusions:

1) there's no way this is a real GMAT question, since it is not possible to solve it algebraically without a calculator; or

2) the poster mistyped the question and this should be a simple interest question instead of compound interest, i.e. the stock grows by a fixed value each quarter instead of by a multiplier, in which case heshamelaziry has posted the correct solution.

For everyone reading this thread, but especially the original poster, ALWAYS include the source of your question and the answer choices. At least if we had answer choices we could figure out if the question is posted correctly and discuss strategic approaches, which every hopeful GMAT star needs to master.
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Re: each quarter

by kaulnikhil » Tue Sep 01, 2009 12:33 pm
shahdevine wrote:At the end of each quarter-year the value of the stock of a certain company is x times more expensive. If at the start of first quarter of 1980 the price of the stock was $3 and at the end of the last quarter of 1985 the price of the stock was $9, what is x?

will post oa after some discussion.
what if we go in this fashion
`3,3x,3x^2,3x^3.......3x^18
3x^18 = 9 . doesn't this mean it is increasing by x ?\

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Re: each quarter

by Stuart@KaplanGMAT » Tue Sep 01, 2009 12:46 pm
kaulnikhil wrote:
shahdevine wrote:At the end of each quarter-year the value of the stock of a certain company is x times more expensive. If at the start of first quarter of 1980 the price of the stock was $3 and at the end of the last quarter of 1985 the price of the stock was $9, what is x?

will post oa after some discussion.
what if we go in this fashion
`3,3x,3x^2,3x^3.......3x^18
3x^18 = 9 . doesn't this mean it is increasing by x ?\
You're correct to a certain degree - I mislabelled the interest rate as x, when in fact the multiplier is x.

So, my set up should have been:

Total of Principle + Interest = P(1 + r)^t

P = starting principle
1 + r = multiplier per compound period
t = # of compound periods

In this question:


Total of Principle + Interest = 9
P = 3
1 + r = x
t = 24 (6 years, compounded quarterly)

and the equation should have been:

9 = 3*(x)^24

which reduces to:

3 = x^24

and

x = 3^(1/24)

However, we still can't possibly solve for the 24th root of 3.

If the poster had included answer choices, and one of the choices was, in fact "3^(1/24)", then this could be an actual GMAT question (although a very high level one). Sadly, we have no choices to check.
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