M7MBA wrote: ↑Sun Jun 21, 2020 2:24 pm
\(M\) and \(N\) working together, can finish a job in 6 days. With the help of \(P,\) they completed the job in 4 days. If \(Q\) joined them, all 4 together would have completed the job in \(3\frac13\) days. If all work at their respective constant rate, then in how many days \(Q\) alone can complete the work?
A. 10
B. 12
C. 15
D. 18
E. 20
[spoiler]OA=E[/spoiler]
Source: e-GMAT
Given that \(M\) and \(N\) working together, can finish a job in 6 days, let's club M and N and rename them R.
So, we have
R can finish a job in 6 days;
R & P working together can finish a job in 4 days;
Let's club R and P and rename them S.
So, we have
=> S can finish a job in 4 days
S & Q working together can finish a job in \(3\frac13\) days
With these data, we deduce
No. of days required for Q to finish the job = Reciprocal of \(\frac1{3\frac13}) – \frac14 = \frac 3{10} - \frac14=\frac{6-5}{20}=\frac1{20}\)
= 20 days
Correct answer:
E
Hope this helps!
-Jay
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