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by sanju09 » Tue Sep 14, 2010 6:20 am
Out of a circular disc of radius 6, a small segment is cut along a chord of length 6. What area is cut as the small segment?
(A) 2 π - 3 √3
(B) 4 π - 4 √3
(C) 4 π - 9 √3
(D) 6 π - 6 √3
(E) 6 π - 9 √3



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by [email protected] » Tue Sep 14, 2010 7:20 am
If a choard length and redius are equal (ie 6), then we have an equilaterral traingle of length 6. in the circle.

Area in question = (Area of a sector of circle with 60 degree angle) - (area of an equilateral traingle with side equals to 6 unit)


= (@/360) X Pie X r^2 - (Sq root of 3)/4 X (Side Squre)^2
= 6 Pie - 9 Sq Root of 3


So it should be E
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