BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

must be true

Expert replies
Source: — Problem Solving |

by shrikantkamble » Fri Jul 11, 2008 8:21 pm
Hi CITI29,

Can you please write whole problem. I am not able to interpret it correctly.
Thanks & Regards,
Shrikant
Join the discussion

by lunarpower » Fri Jul 11, 2008 8:36 pm
hey.

when you post problems like this one, with lots of "<" and ">" signs, you have to disable HTML. otherwise, the forum will "think" that all the inequality signs are actually html tags, and will interpret them accordingly - an action that includes ignoring all the text between a "<" and a ">" if it doesn't constitute a valid html tag.

therefore, large swaths of your text are disappearing from the problem.

to fix this: check the Disable HTML in this post box underneath the text when you're posting.
Ron has been teaching various standardized tests for 20 years.

--

Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi

--

Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.

Yves Saint-Laurent

--

Learn more about ron
Join the discussion

by CITI29 » Sun Jul 13, 2008 6:28 am
thanks Ron...i'm posting the question again
---------

If d > 0 and 0 < 1-c/d < 1, which of the following
must be true?
I. c > 0
II. c/d < 1
III. c2 + d 2 > 1

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
Join the discussion

by raunekk » Sun Jul 13, 2008 9:43 am
IMO:C

#3 cannot be true because if c=1/3 and d = 1/2 then,

c^2 + d ^2 is not greater than 1
Join the discussion

by sudhir3127 » Sun Jul 13, 2008 10:07 am
my answer is C as well.
Join the discussion

by beeparoo » Tue Jul 15, 2008 9:56 am
If d > 0 and 0 < 1-(c/d) <1> 0
II. c/d <1> 1

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
You should make use of some brackets so as not to confuse other readers who may interpret your question one of two ways:

a) 1-(c/d) <-- Which I assume is what you meant

b) (1-c)/d

See the difference?
Join the discussion