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must be true

by CITI29 » Fri Jul 11, 2008 7:16 pm
If d > 0 and 0 < d
1&#8722; c <1> 0
II. d
c <1> 1

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
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by shrikantkamble » Fri Jul 11, 2008 8:21 pm
Hi CITI29,

Can you please write whole problem. I am not able to interpret it correctly.
Thanks & Regards,
Shrikant
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by lunarpower » Fri Jul 11, 2008 8:36 pm
hey.

when you post problems like this one, with lots of "<" and ">" signs, you have to disable HTML. otherwise, the forum will "think" that all the inequality signs are actually html tags, and will interpret them accordingly - an action that includes ignoring all the text between a "<" and a ">" if it doesn't constitute a valid html tag.

therefore, large swaths of your text are disappearing from the problem.

to fix this: check the Disable HTML in this post box underneath the text when you're posting.
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by CITI29 » Sun Jul 13, 2008 6:28 am
thanks Ron...i'm posting the question again
---------

If d > 0 and 0 < 1-c/d < 1, which of the following
must be true?
I. c > 0
II. c/d < 1
III. c2 + d 2 > 1

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
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by raunekk » Sun Jul 13, 2008 9:43 am
IMO:C

#3 cannot be true because if c=1/3 and d = 1/2 then,

c^2 + d ^2 is not greater than 1
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by sudhir3127 » Sun Jul 13, 2008 10:07 am
my answer is C as well.
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by beeparoo » Tue Jul 15, 2008 9:56 am
If d > 0 and 0 < 1-(c/d) <1> 0
II. c/d <1> 1

(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II, and III
You should make use of some brackets so as not to confuse other readers who may interpret your question one of two ways:

a) 1-(c/d) <-- Which I assume is what you meant

b) (1-c)/d

See the difference?
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