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gmat_perfect
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Please show me the ways to solve the following problem:
n! =90*2*(n-2)!
How can I get the value of n?
We know,
n! =n(n-1)!
Then (n-2)! =?
Thanks.
n! =90*2*(n-2)!
How can I get the value of n?
We know,
n! =n(n-1)!
Then (n-2)! =?
Thanks.
