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GMAC paper based tests

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Re: GMAC paper based tests

by jayhawk2001 » Fri May 25, 2007 7:47 am
We have the following 4 combinations:

(x = +ve or -ve) * (y = +ve or -ve)

2x - 3y <= -6

When x is positive and y is negative, 2x - 3y will yield a positive
number and so cannot be <= -6.

Hence quadrant IV will not have a point x,y that satisfies the eqn.

Now, if we are given options like I & II or II & IV, it might have
gotten messier but since options are unique, we can converge on
this quickly.
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by Cybermusings » Fri May 25, 2007 9:33 am
Hey tell me something....Can we also plot the line 2x-3y = -6 and then determine the region which does not satisfy the inequality 2x-3x<= -6...Is that a good idea as well....I did that and honestly didn't take much time....
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by jayhawk2001 » Fri May 25, 2007 2:42 pm
Cybermusings wrote:Hey tell me something....Can we also plot the line 2x-3y = -6 and then determine the region which does not satisfy the inequality 2x-3x<= -6...Is that a good idea as well....I did that and honestly didn't take much time....
Yup, I guess that would work as well. However, in the process of plotting
this graph, would you not get to know that quadrant IV doesn't come into
the picture at all ?
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